security key works
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.gitignore
vendored
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.gitignore
vendored
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*.txt
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.venv/
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93
key_engine.py
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93
key_engine.py
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import hashlib
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import secrets
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from mnemonic import Mnemonic # 仅用于标准的助记词转换
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class SentinelKeyEngine:
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def __init__(self):
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self.mnemo = Mnemonic("english")
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def generate_vault_keys(self):
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"""
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1. 生成原始 12 助记词 (Master Key)
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"""
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words = self.mnemo.generate(strength=128)
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entropy = self.mnemo.to_entropy(words)
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return words, entropy
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def split_to_shares(self, entropy):
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"""
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2. SSS (3,2) 门限分片逻辑
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公式: f(x) = S + a*x (直线方程,S为秘密,a为随机斜率)
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我们将秘密 S 分成 3 份,任选 2 份即可恢复
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"""
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# 将熵转换为大整数
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secret_int = int.from_bytes(entropy, 'big')
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# 生成一个随机系数 a (安全性需与秘密强度一致)
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# 这里使用 secrets 保证加密级随机
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a = int.from_bytes(secrets.token_bytes(16), 'big')
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# 定义 3 个点: x=1, x=2, x=3
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# Share = (x, f(x))
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def f(x): return secret_int + a * x
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share1 = (1, f(1)) # 手机分片
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share2 = (2, f(2)) # 云端分片
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share3 = (3, f(3)) # 传承卡分片
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return [share1, share2, share3]
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def recover_from_shares(self, share_a, share_b):
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"""
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3. 恢复逻辑:拉格朗日插值还原
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已知 (x1, y1) 和 (x2, y2),求 f(0) 即秘密 S
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公式: S = (x2*y1 - x1*y2) / (x2 - x1)
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"""
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x1, y1 = share_a
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x2, y2 = share_b
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# 还原常数项 S
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secret_int = (x2 * y1 - x1 * y2) // (x2 - x1)
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# 转回字节并生成助记词
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recovered_entropy = secret_int.to_bytes(16, 'big')
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return self.mnemo.to_mnemonic(recovered_entropy)
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if __name__ == "__main__":
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# --- Sentinel 协议业务流程模拟 ---
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engine = SentinelKeyEngine()
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# [生前]:初始化金库
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master_words, entropy = engine.generate_vault_keys()
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print(f"【1. 生成原始助记词】: {master_words}")
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shares = engine.split_to_shares(entropy)
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print(f"【2. SSS 分片完成】:")
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print(f" - 分片1 (手机安全区): {shares[0]}")
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print(f" - 分片2 (Sentinel云): {shares[1]}")
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print(f" - 分片3 (传承卡单词): {shares[2]}")
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print("-" * 50)
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# [死后/传承]:模拟用户失联,触发被动验证
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# 假设继承人拿着卡片 (Share 3),向服务器请求分片 (Share 2)
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successor_share = shares[2]
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server_share = shares[1]
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# 执行恢复
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recovered_words = engine.recover_from_shares(shares[0], shares[1])
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print(f"【1. 手机+云 : {recovered_words}")
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recovered_words = engine.recover_from_shares(shares[0], shares[2])
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print(f"【2. 手机+传承卡 : {recovered_words}")
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recovered_words = engine.recover_from_shares(shares[1], shares[2])
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print(f"【3. 云+传承卡 : {recovered_words}")
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# 校验一致性
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assert recovered_words == master_words
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print("\n结果:恢复出的助记词与原始完全一致。")
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with open("words.txt", "w") as f:
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f.write("%s\n"%master_words)
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76
slice_crypt.py
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slice_crypt.py
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import os
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from mnemonic import Mnemonic
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from Crypto.Cipher import AES
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from Crypto.Protocol.KDF import PBKDF2
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from Crypto.Util.Padding import pad, unpad
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class SentinelVault:
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def __init__(self, salt=b'Sentinel_Salt_2026'): # 固定的盐值,用于增加派生强度
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self.mnemo = Mnemonic("english")
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self.salt = salt
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def derive_key(self, mnemonic_phrase):
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"""
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使用 PBKDF2 将助记词转换为 AES-256 密钥 (32 bytes)
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"""
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# 种子生成遵循 BIP-39 逻辑
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seed = self.mnemo.to_seed(mnemonic_phrase, passphrase="")
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# 派生出一个 32 字节的强密钥
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key = PBKDF2(seed, self.salt, dkLen=32, count=100000)
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return key
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def encrypt_data(self, key, plaintext):
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"""
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使用 AES-256 GCM 模式进行加密 (具备完整性校验)
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"""
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cipher = AES.new(key, AES.MODE_GCM)
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nonce = cipher.nonce
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ciphertext, tag = cipher.encrypt_and_digest(plaintext.encode('utf-8'))
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# 返回:随机数 + 校验位 + 密文
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return nonce + tag + ciphertext
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def decrypt_data(self, key, encrypted_blob):
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"""
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AES-256 GCM 解密
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"""
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nonce = encrypted_blob[:16]
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tag = encrypted_blob[16:32]
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ciphertext = encrypted_blob[32:]
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cipher = AES.new(key, AES.MODE_GCM, nonce=nonce)
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try:
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plaintext = cipher.decrypt_and_verify(ciphertext, tag)
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return plaintext.decode('utf-8')
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except ValueError:
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return "【解密失败】:密钥错误或数据被篡改"
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if __name__ == "__main__":
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# --- 模拟 Sentinel 协议完整业务流 ---
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# 1. 假设这是通过之前 SSS 算法恢复出来的 12 词
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recovered_mnemonic = "apple banana cherry dog elephant fish goat horse ice jacket kangaroo lion"
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try:
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with open("words.txt", "r") as f:
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recovered_mnemonic = f.read().strip()
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except FileNotFoundError:
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print("words.txt 文件未找到,使用默认助记词进行演示。")
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print(f"Demo助记词:{recovered_mnemonic}")
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vault = SentinelVault()
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# 2. 生成加密密钥
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aes_key = vault.derive_key(recovered_mnemonic)
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aes_key_hex = aes_key.hex()
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print(f"【密钥派生完成】:len:{len(aes_key_hex)} -> {aes_key_hex[:20]}...")
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# 3. 用户生前加密资产(如:银行账户、数字遗产)
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my_legacy = "我的瑞士银行账号是:CH123456789,密码是:Sentinel2026"
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print(f"【Demo资产信息】:{my_legacy}")
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encrypted_asset = vault.encrypt_data(aes_key, my_legacy)
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encrypted_asset_hex = encrypted_asset.hex()
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print(f"【数据已加密】:len:{len(encrypted_asset_hex)} -> {encrypted_asset_hex[:40]}...")
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# 4. 模拟继承人通过分片拼凑后进行解密
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print("-" * 50)
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decrypted_content = vault.decrypt_data(aes_key, encrypted_asset)
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print(f"【继承人解密成功】:{decrypted_content}")
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